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-0.06x^2+0.58x+1.5=0
a = -0.06; b = 0.58; c = +1.5;
Δ = b2-4ac
Δ = 0.582-4·(-0.06)·1.5
Δ = 0.6964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.58)-\sqrt{0.6964}}{2*-0.06}=\frac{-0.58-\sqrt{0.6964}}{-0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.58)+\sqrt{0.6964}}{2*-0.06}=\frac{-0.58+\sqrt{0.6964}}{-0.12} $
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